Optimal. Leaf size=174 \[ \frac{b \left (3 a^2+2 b^2\right ) \tan ^6(c+d x)}{6 d}+\frac{a \left (a^2+6 b^2\right ) \tan ^5(c+d x)}{5 d}+\frac{b \left (6 a^2+b^2\right ) \tan ^4(c+d x)}{4 d}+\frac{a \left (2 a^2+3 b^2\right ) \tan ^3(c+d x)}{3 d}+\frac{3 a^2 b \tan ^2(c+d x)}{2 d}+\frac{a^3 \tan (c+d x)}{d}+\frac{3 a b^2 \tan ^7(c+d x)}{7 d}+\frac{b^3 \tan ^8(c+d x)}{8 d} \]
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Rubi [A] time = 0.13956, antiderivative size = 174, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 2, integrand size = 28, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.071, Rules used = {3088, 948} \[ \frac{b \left (3 a^2+2 b^2\right ) \tan ^6(c+d x)}{6 d}+\frac{a \left (a^2+6 b^2\right ) \tan ^5(c+d x)}{5 d}+\frac{b \left (6 a^2+b^2\right ) \tan ^4(c+d x)}{4 d}+\frac{a \left (2 a^2+3 b^2\right ) \tan ^3(c+d x)}{3 d}+\frac{3 a^2 b \tan ^2(c+d x)}{2 d}+\frac{a^3 \tan (c+d x)}{d}+\frac{3 a b^2 \tan ^7(c+d x)}{7 d}+\frac{b^3 \tan ^8(c+d x)}{8 d} \]
Antiderivative was successfully verified.
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Rule 3088
Rule 948
Rubi steps
\begin{align*} \int \sec ^9(c+d x) (a \cos (c+d x)+b \sin (c+d x))^3 \, dx &=-\frac{\operatorname{Subst}\left (\int \frac{(b+a x)^3 \left (1+x^2\right )^2}{x^9} \, dx,x,\cot (c+d x)\right )}{d}\\ &=-\frac{\operatorname{Subst}\left (\int \left (\frac{b^3}{x^9}+\frac{3 a b^2}{x^8}+\frac{3 a^2 b+2 b^3}{x^7}+\frac{a^3+6 a b^2}{x^6}+\frac{6 a^2 b+b^3}{x^5}+\frac{2 a^3+3 a b^2}{x^4}+\frac{3 a^2 b}{x^3}+\frac{a^3}{x^2}\right ) \, dx,x,\cot (c+d x)\right )}{d}\\ &=\frac{a^3 \tan (c+d x)}{d}+\frac{3 a^2 b \tan ^2(c+d x)}{2 d}+\frac{a \left (2 a^2+3 b^2\right ) \tan ^3(c+d x)}{3 d}+\frac{b \left (6 a^2+b^2\right ) \tan ^4(c+d x)}{4 d}+\frac{a \left (a^2+6 b^2\right ) \tan ^5(c+d x)}{5 d}+\frac{b \left (3 a^2+2 b^2\right ) \tan ^6(c+d x)}{6 d}+\frac{3 a b^2 \tan ^7(c+d x)}{7 d}+\frac{b^3 \tan ^8(c+d x)}{8 d}\\ \end{align*}
Mathematica [A] time = 0.597798, size = 115, normalized size = 0.66 \[ \frac{\frac{1}{3} \left (3 a^2+b^2\right ) (a+b \tan (c+d x))^6-\frac{4}{5} a \left (a^2+b^2\right ) (a+b \tan (c+d x))^5+\frac{1}{4} \left (a^2+b^2\right )^2 (a+b \tan (c+d x))^4+\frac{1}{8} (a+b \tan (c+d x))^8-\frac{4}{7} a (a+b \tan (c+d x))^7}{b^5 d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.128, size = 173, normalized size = 1. \begin{align*}{\frac{1}{d} \left ( -{a}^{3} \left ( -{\frac{8}{15}}-{\frac{ \left ( \sec \left ( dx+c \right ) \right ) ^{4}}{5}}-{\frac{4\, \left ( \sec \left ( dx+c \right ) \right ) ^{2}}{15}} \right ) \tan \left ( dx+c \right ) +{\frac{{a}^{2}b}{2\, \left ( \cos \left ( dx+c \right ) \right ) ^{6}}}+3\,a{b}^{2} \left ( 1/7\,{\frac{ \left ( \sin \left ( dx+c \right ) \right ) ^{3}}{ \left ( \cos \left ( dx+c \right ) \right ) ^{7}}}+{\frac{4\, \left ( \sin \left ( dx+c \right ) \right ) ^{3}}{35\, \left ( \cos \left ( dx+c \right ) \right ) ^{5}}}+{\frac{8\, \left ( \sin \left ( dx+c \right ) \right ) ^{3}}{105\, \left ( \cos \left ( dx+c \right ) \right ) ^{3}}} \right ) +{b}^{3} \left ({\frac{ \left ( \sin \left ( dx+c \right ) \right ) ^{4}}{8\, \left ( \cos \left ( dx+c \right ) \right ) ^{8}}}+{\frac{ \left ( \sin \left ( dx+c \right ) \right ) ^{4}}{12\, \left ( \cos \left ( dx+c \right ) \right ) ^{6}}}+{\frac{ \left ( \sin \left ( dx+c \right ) \right ) ^{4}}{24\, \left ( \cos \left ( dx+c \right ) \right ) ^{4}}} \right ) \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.28866, size = 208, normalized size = 1.2 \begin{align*} \frac{56 \,{\left (3 \, \tan \left (d x + c\right )^{5} + 10 \, \tan \left (d x + c\right )^{3} + 15 \, \tan \left (d x + c\right )\right )} a^{3} + 24 \,{\left (15 \, \tan \left (d x + c\right )^{7} + 42 \, \tan \left (d x + c\right )^{5} + 35 \, \tan \left (d x + c\right )^{3}\right )} a b^{2} + \frac{35 \,{\left (4 \, \sin \left (d x + c\right )^{2} - 1\right )} b^{3}}{\sin \left (d x + c\right )^{8} - 4 \, \sin \left (d x + c\right )^{6} + 6 \, \sin \left (d x + c\right )^{4} - 4 \, \sin \left (d x + c\right )^{2} + 1} - \frac{420 \, a^{2} b}{{\left (\sin \left (d x + c\right )^{2} - 1\right )}^{3}}}{840 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 0.512588, size = 304, normalized size = 1.75 \begin{align*} \frac{105 \, b^{3} + 140 \,{\left (3 \, a^{2} b - b^{3}\right )} \cos \left (d x + c\right )^{2} + 8 \,{\left (8 \,{\left (7 \, a^{3} - 3 \, a b^{2}\right )} \cos \left (d x + c\right )^{7} + 4 \,{\left (7 \, a^{3} - 3 \, a b^{2}\right )} \cos \left (d x + c\right )^{5} + 45 \, a b^{2} \cos \left (d x + c\right ) + 3 \,{\left (7 \, a^{3} - 3 \, a b^{2}\right )} \cos \left (d x + c\right )^{3}\right )} \sin \left (d x + c\right )}{840 \, d \cos \left (d x + c\right )^{8}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.18352, size = 224, normalized size = 1.29 \begin{align*} \frac{105 \, b^{3} \tan \left (d x + c\right )^{8} + 360 \, a b^{2} \tan \left (d x + c\right )^{7} + 420 \, a^{2} b \tan \left (d x + c\right )^{6} + 280 \, b^{3} \tan \left (d x + c\right )^{6} + 168 \, a^{3} \tan \left (d x + c\right )^{5} + 1008 \, a b^{2} \tan \left (d x + c\right )^{5} + 1260 \, a^{2} b \tan \left (d x + c\right )^{4} + 210 \, b^{3} \tan \left (d x + c\right )^{4} + 560 \, a^{3} \tan \left (d x + c\right )^{3} + 840 \, a b^{2} \tan \left (d x + c\right )^{3} + 1260 \, a^{2} b \tan \left (d x + c\right )^{2} + 840 \, a^{3} \tan \left (d x + c\right )}{840 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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